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We want the standard enthalpy of formation for ca (oh)_2 Calculate moles of acid, calculate moles of base Thus, our required equation is the equation where all the constituent elements combine to form the compound, i.e.

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The acid in excess is then titrated with n aoh (aq) of known concentration.we can thus get back to the concentration or molar quantity of m (oh)2.as it stands the question (and answer) are hypothetical. Nickel (ii)hydroxide may be formed without or (more likely. So this is a propanol derivative

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Both names seem to be unambiguous.

The longer the alkyl chain attached to the hydroxyl head, usually the more basic the conjugate base is (and the less nucleophilic). 6.3072 g >>molarity = moles of solute/volume of solution (in litres) 0.45 m = n/0.4 l n = 0.45 m × 0.4 l = 0.18 mol you need 0.18 mol of nh_4oh molar mass of nh_4oh is 35.04 g/mol mass of solute = 0.18 cancelmol × 35.04 g/cancelmol = 6.3072 g Because n aoh → n a+ + oh − and n i2+ + 2oh −→n i(oh)2 total mols of n aoh 60ml ⋅ 0.45m ol/l = 27mm ol of n aoh (dont forget the m for milli=one thousandth) this will produce 27 2 = 13.5mm ol of n i(oh)2 now you multiply this by the molecular mass number to get the weight in milligrams (divide by 1000 to get the grams)